Area, Surface Area and Volume: Question 3

Syllabus C5.2, E5.2, C5.4, E5.4

Multiple choice Extended 3 marks

A solid metal paperweight is made in the shape of a right circular cone. The cone has a base radius of 6 cm6\text{ cm} and a perpendicular height of 14 cm14\text{ cm}.

Taking π=3.142\pi = 3.142, which of the following is the volume of the paperweight, correct to 33 significant figures?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Choose the correct formula

The solid is a cone, so use the volume of a cone:

V=13πr2hV = \frac{1}{3}\pi r^2 h

The key features are the factor 13\tfrac{1}{3} (a cone fills one third of the enclosing cylinder) and that the radius is squared, not the height.

Step 2: Substitute the values

Here r=6 cmr = 6\text{ cm} and h=14 cmh = 14\text{ cm}:

V=13π(6)2(14)V = \frac{1}{3}\,\pi \,(6)^2(14)

Work out the numbers inside step by step:

(6)2=36,36×14=504(6)^2 = 36, \qquad 36 \times 14 = 504

So

V=13π×504=168π.V = \frac{1}{3}\,\pi \times 504 = 168\,\pi.

Step 3: Evaluate

Using π=3.142\pi = 3.142:

V=168×3.142=527.856528 cm3 (3 s.f.)V = 168 \times 3.142 = 527.856 \approx 528\text{ cm}^3 \ (3\text{ s.f.})

(Using the more precise π\pi on a calculator gives 527.79527.79\ldots, which also rounds to 528 cm3528\text{ cm}^3.)

Why the other options are wrong

  • 1580 cm31580\text{ cm}^3 comes from forgetting the 13\tfrac{1}{3} and computing the full cylinder πr2h=504π\pi r^2 h = 504\pi.
  • 905 cm3905\text{ cm}^3 comes from using the sphere formula 43πr3=288π\tfrac{4}{3}\pi r^3 = 288\pi, which wrongly ignores the height.
  • 2110 cm32110\text{ cm}^3 comes from using the diameter 1212 in place of the radius: 13π(12)2(14)=672π\tfrac{1}{3}\pi(12)^2(14) = 672\pi.

Final answer

V528 cm3\boxed{V \approx 528\text{ cm}^3}

So the correct option is A.