Area, Surface Area and Volume: Question 6

Syllabus C5.2, E5.2, C5.4, E5.4

Structured Extended 5 marks

A company makes solid closed cylinders out of aluminium to use as rollers.

Each cylinder has radius 4.54.5 cm and height 1111 cm.

(a) Work out the volume of one cylinder. Give your answer correct to 3 significant figures. [3]

(b) Work out the total surface area of one cylinder. Give your answer correct to 3 significant figures. [2]

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Worked solution

Part (a): Volume of the cylinder

The volume of a cylinder is given by

V=πr2hV = \pi r^2 h

Here the radius is r=4.5r = 4.5 cm and the height is h=11h = 11 cm. Substituting these values:

V=π×(4.5)2×11V = \pi \times (4.5)^2 \times 11

First square the radius:

(4.5)2=20.25(4.5)^2 = 20.25

Then multiply through:

V=π×20.25×11=222.75πV = \pi \times 20.25 \times 11 = 222.75\pi

V=699.789 cm3V = 699.789\ldots \text{ cm}^3

Rounding to 3 significant figures:

V=700 cm3V = 700 \text{ cm}^3

Part (b): Total surface area of the cylinder

The cylinder is closed, so its surface is made of the curved side plus the two flat circular ends.

Curved surface area:

Acurved=2πrh=2π×4.5×11=99π=311.017 cm2A_{\text{curved}} = 2\pi r h = 2\pi \times 4.5 \times 11 = 99\pi = 311.017\ldots \text{ cm}^2

Two circular ends:

Aends=2πr2=2π×(4.5)2=2π×20.25=40.5π=127.234 cm2A_{\text{ends}} = 2\pi r^2 = 2\pi \times (4.5)^2 = 2\pi \times 20.25 = 40.5\pi = 127.234\ldots \text{ cm}^2

Total surface area:

A=2πrh+2πr2=2πr(r+h)A = 2\pi r h + 2\pi r^2 = 2\pi r (r + h)

A=2π×4.5×(4.5+11)=9π×15.5=139.5πA = 2\pi \times 4.5 \times (4.5 + 11) = 9\pi \times 15.5 = 139.5\pi

A=438.252 cm2A = 438.252\ldots \text{ cm}^2

Rounding to 3 significant figures:

A=438 cm2A = 438 \text{ cm}^2

Summary

  • Volume: 700\mathbf{700} cm3^3 (3 s.f.)
  • Total surface area: 438\mathbf{438} cm2^2 (3 s.f.)

Notice how using the factorised form 2πr(r+h)2\pi r(r+h) for the surface area saves work and helps avoid missing one of the ends. Keep full accuracy in your calculator and only round at the very end.