Standard Form: Question 4

Syllabus C1.8, E1.8

Structured Core 6 marks

The distance from a space probe to a distant moon is 5040000 km5\,040\,000\text{ km}.

(a) Write 50400005\,040\,000 in standard form. [1]

(b) The width of a grain of pollen is 3.7×104 m3.7 \times 10^{-4}\text{ m}. Write this number as an ordinary (decimal) number. [1]

(c) Work out (6×108)×(1.5×103)(6 \times 10^{8}) \times (1.5 \times 10^{-3}). Give your answer in standard form. [2]

(d) Write down which is larger, 8×1058 \times 10^{5} or 2×1062 \times 10^{6}, and explain your answer. [2]

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Worked solution

Part (a)

We need to write 50400005\,040\,000 in the form a×10na \times 10^{n}, where 1a<101 \le a < 10 and nn is an integer.

Step 1: Place the decimal point so that aa is between 1 and 10.

Starting from 5040000.05\,040\,000.0, the decimal point must sit just after the first non-zero digit:

5.040000    a=5.045.040000\ldots \;\Rightarrow\; a = 5.04

Step 2: Count how many places the decimal point moved.

From 5040000.5\,040\,000. to 5.045.04 the point moves 66 places to the left, so n=6n = 6.

5040000=5.04×106\boxed{5\,040\,000 = 5.04 \times 10^{6}}

Check: 5.04×106=5.04×1000000=50400005.04 \times 10^{6} = 5.04 \times 1\,000\,000 = 5\,040\,000. ✓


Part (b)

The number is 3.7×104 m3.7 \times 10^{-4}\text{ m}. A negative index means the number is small (less than 1), so the decimal point moves to the left.

Step: Move the decimal point 4 places to the left.

3.7    0.37    0.037    0.0037    0.000373.7 \;\to\; 0.37 \;\to\; 0.037 \;\to\; 0.0037 \;\to\; 0.00037

3.7×104=0.00037\boxed{3.7 \times 10^{-4} = 0.00037}

Check: 0.00037×104=0.00037×10000=3.70.00037 \times 10^{4} = 0.00037 \times 10\,000 = 3.7. ✓


Part (c)

Work out (6×108)×(1.5×103)(6 \times 10^{8}) \times (1.5 \times 10^{-3}).

Step 1: Multiply the number parts (aa values).

6×1.5=96 \times 1.5 = 9

Step 2: Multiply the powers of 10 by adding the indices.

108×103=108+(3)=10510^{8} \times 10^{-3} = 10^{8 + (-3)} = 10^{5}

Step 3: Combine.

9×1059 \times 10^{5}

Here a=9a = 9 satisfies 1a<101 \le a < 10, so the answer is already in standard form.

(6×108)×(1.5×103)=9×105\boxed{(6 \times 10^{8}) \times (1.5 \times 10^{-3}) = 9 \times 10^{5}}

Check: 6×108=6000000006 \times 10^{8} = 600\,000\,000 and 1.5×103=0.00151.5 \times 10^{-3} = 0.0015; then 600000000×0.0015=900000=9×105600\,000\,000 \times 0.0015 = 900\,000 = 9 \times 10^{5}. ✓


Part (d)

Compare 8×1058 \times 10^{5} and 2×1062 \times 10^{6}.

Method: compare the powers of 10 first.

For numbers in standard form, the one with the larger power of 10 is larger (provided each aa is between 1 and 10). Here:

106>10510^{6} > 10^{5}

so 2×1062 \times 10^{6} is larger, even though its aa-value (22) is smaller than 88.

2×106 is larger\boxed{2 \times 10^{6} \text{ is larger}}

Check by writing as ordinary numbers:

8×105=800000,2×106=20000008 \times 10^{5} = 800\,000, \qquad 2 \times 10^{6} = 2\,000\,000

and 2000000>8000002\,000\,000 > 800\,000. ✓