Circle Theorems: O-Level / IGCSE Maths (0580)

Syllabus E4.7, E4.8 · Strand 4 Geometry

Questions
3
Total marks
15
Tier mix
0 Core · 3 Extended

This topic looks at the special angle relationships that arise when straight lines, chords and tangents meet a circle, covering syllabus objectives E4.7 and E4.8. The central idea is a small collection of circle theorems that link angles drawn inside or around a circle to one another, allowing you to find unknown angles by reasoning rather than measurement. The key results are: the angle subtended at the centre is twice the angle subtended at the circumference from the same arc (angle at centre=2×angle at circumference\text{angle at centre} = 2 \times \text{angle at circumference}); the angle in a semicircle is a right angle (9090^{\circ}); angles in the same segment are equal; opposite angles of a cyclic quadrilateral sum to 180180^{\circ}; and the two tangents drawn from an external point are equal in length, each meeting the radius at 9090^{\circ}.

The usual method is to identify which theorem applies to the figure, write down the angle relationship it gives, then combine it with familiar facts such as angles in a triangle summing to 180180^{\circ}, the base angles of an isosceles triangle (often formed by two radii) being equal, or angles on a straight line summing to 180180^{\circ}. Many exam-style questions chain two or three of these steps together, so it helps to label each angle and state the reason at every stage. Always check whether two angles stand on the same arc before equating them, and watch for radii, diameters and tangents, since these unlock the semicircle and tangent results.

The worked examples below are original, written from the syllabus objective to show how each theorem is selected and applied, with every step of the worked solution justified.

Question 1

Structured Extended 7 marks

AA, BB, CC and DD are points on a circle with centre OO.

AOCAOC is a straight line, so ACAC is a diameter of the circle. The points BB and DD lie on the circle on opposite sides of ACAC (with BB to the upper right and DD to the lower left).

You are given that BAC=35andDOC=80,\angle BAC = 35^\circ \qquad \text{and} \qquad \angle DOC = 80^\circ, where DOC\angle DOC is the angle at the centre OO.

(a) Write down the size of ABC\angle ABC. Give a geometrical reason for your answer. [2]

(b) Work out the size of BCA\angle BCA. [1]

(c) Find the size of DBC\angle DBC. State the circle theorem that you use. [2]

(d) Find the size of OCD\angle OCD. [2]

Question 2

Structured Extended 7 marks

A, B, C and D are four points on a circle, labelled in order around the circumference. The chords AC and BD are drawn and intersect at the point E inside the circle.

You are given that

  • angle BAC = 47°
  • angle CAD = 61°
  • angle ABD = 31°

(a) Find angle BDC, giving a reason for your answer. [2]

(b) Write down the size of angle DBC, giving a reason for your answer. [1]

(c) Hence find angle ADC. [2]

(d) Find angle BCD. [2]

Question 3

Multiple choice Extended 1 mark

PAQPAQ is a straight line that is a tangent to a circle at the point AA. BB and CC are points on the circle, and CC lies on the major arc ABAB (in the alternate segment, on the opposite side of the chord ABAB from PP). The chord ABAB makes an angle of 6464^{\circ} with the tangent, so that angle PAB=64PAB = 64^{\circ}.

Work out the size of angle ACBACB.