Linear Equations and Inequalities: O-Level / IGCSE Maths (0580)

Syllabus C2.5, E2.5, C2.6, E2.6 · Strand 2 Algebra and graphs

Questions
3
Total marks
15
Tier mix
1 Core · 2 Extended

This topic brings together the algebra of straight-line relationships: solving linear equations in one unknown, solving simultaneous linear equations in two unknowns, and solving and representing linear inequalities. A linear equation such as 3x7=113x - 7 = 11 contains an unknown only to the first power, and the goal is to isolate that unknown by applying the same operation to both sides until it stands alone, for example adding 77 then dividing by 33 to obtain x=6x = 6. The same balancing idea extends to equations with brackets, fractions, or the unknown appearing on both sides.

When two unknowns are involved, a single equation is not enough to pin down their values, so we work with a pair of equations at once. The two standard techniques are elimination, where the equations are added or subtracted (after scaling if needed) to remove one variable, and substitution, where one equation is rearranged to make one variable the subject and then put into the other. Both methods reduce the problem to a single linear equation, after which the second value follows; the solution (x,y)(x, y) is the point where the two lines meet. Inequalities are handled much like equations, with one key rule: multiplying or dividing by a negative number reverses the inequality sign, as in 2x>6x<3-2x > 6 \Rightarrow x < -3. Solutions are often shown on a number line, using an open circle for strict inequalities (<<, >>) and a filled circle for inclusive ones (\le, \ge).

Mastering these methods builds directly on rearranging formulae and underpins later work on graphs, regions, and problem-solving across the syllabus. The worked examples below are original, written from the syllabus objective to illustrate each method with full, step-by-step solutions.

Question 1

Structured Core 7 marks

Solve each of the following linear equations. Show your working.

(a)   4(x+3)=2(x+9)\;4(x + 3) = 2(x + 9) [3]

(b)   203(x1)=2(x+4)+5\;20 - 3(x - 1) = 2(x + 4) + 5 [4]

Question 2

Structured Extended 6 marks

A school drama club sells tickets for its end-of-year show. An adult ticket costs aa dollars and a child ticket costs cc dollars.

On Friday the club sells 7 adult tickets and 5 child tickets for a total of $109.

On Saturday the club sells 4 adult tickets and 9 child tickets for a total of $93.

(a) Use the information above to write down two equations in aa and cc. [2]

(b) Solve the simultaneous equations to find the cost of an adult ticket and the cost of a child ticket. Show all your working. [3]

(c) A family buys 2 adult tickets and 3 child tickets. Find the total cost. [1]

Question 3

Multiple choice Extended 2 marks

A number xx satisfies the double inequality 53x2<7.-5 \le 3x - 2 < 7. Which set lists all the integer values of xx that make this inequality true?