Percentages: Question 3

Syllabus C1.13, E1.13

Multiple choice Extended 3 marks

Mariam invests $2,400 in a savings account that pays compound interest at a rate of 4.5%4.5\% per year. She makes no further deposits or withdrawals. Calculate the total amount in the account at the end of 3 years.

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Identify the compound interest formula

For compound interest, the total amount AA after nn years is:

A=P(1+r100)nA = P\left(1 + \frac{r}{100}\right)^{n}

where:

  • P=2400P = 2400 (the principal, in dollars)
  • r=4.5r = 4.5 (the percentage rate per year)
  • n=3n = 3 (the number of years)

Step 2: Substitute the values

A=2400(1+4.5100)3=2400(1.045)3A = 2400\left(1 + \frac{4.5}{100}\right)^{3} = 2400\,(1.045)^{3}

Step 3: Evaluate the power

1.0453=1.045×1.045×1.045=1.1411661.045^{3} = 1.045 \times 1.045 \times 1.045 = 1.141166\ldots

Step 4: Multiply by the principal

A=2400×1.141166=2738.7986A = 2400 \times 1.141166\ldots = 2738.7986\ldots

Rounding to the nearest cent gives 2738.80\boxed{2738.80} dollars.

Why the other options are wrong

  • $2,724.00 comes from using simple interest: 2400+2400×0.045×3=2400+3242400 + 2400 \times 0.045 \times 3 = 2400 + 324. Compound interest earns interest on previous interest, so the true amount is higher.
  • $2,620.86 uses only n=2n = 2 years: 2400×1.04522400 \times 1.045^{2}, the wrong number of years.
  • $338.80 is only the interest earned (2738.8024002738.80 - 2400), not the total amount in the account.

Final Answer

The total amount after 3 years is $2,738.80, which is option A.