Percentages: Question 4

Syllabus C1.13, E1.13

Structured Extended 9 marks

A furniture shop sells desks, chairs and shelving units.

(a) After a price rise of 15 per cent, a desk is now priced at $29.90. Work out the price of the desk before the rise. [2]

(b) A designer office chair is bought for $24000. Its value falls by 12 per cent each year. Work out the value of the chair after 3 years. Give your answer correct to the nearest dollar. [3]

(c) Meera invests $3500 in an account paying 4 per cent per year compound interest. Work out the total interest earned after 5 years. Give your answer correct to 2 decimal places. [4]

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Worked solution

Part (a): Reverse percentage

The $29.90 is the price after a 15 per cent increase, so it represents 100%+15%=115%100\% + 15\% = 115\% of the original price.

Step 1: Write 115 per cent as a multiplier.

115%=115100=1.15115\% = \frac{115}{100} = 1.15

Step 2: Divide the new price by the multiplier to undo the increase.

original price=29.901.15=26\text{original price} = \frac{29.90}{1.15} = 26

Price before the rise=26.00 dollars\text{Price before the rise} = \boxed{26.00}\ \text{dollars}

Check: 26×1.15=29.9026 \times 1.15 = 29.90. ✓ (This confirms we divided rather than subtracted 15 per cent.)


Part (b): Repeated percentage decrease (depreciation)

The value falls by 12 per cent each year. A 12 per cent decrease leaves 100%12%=88%100\% - 12\% = 88\% of the value, so the multiplier for one year is:

88%=0.8888\% = 0.88

Because the same percentage change is applied year after year, we raise the multiplier to the power of the number of years:

value after 3 years=24000×(0.88)3\text{value after 3 years} = 24000 \times (0.88)^{3}

Step 1: Evaluate the multiplier.

(0.88)3=0.88×0.88×0.88=0.681472(0.88)^{3} = 0.88 \times 0.88 \times 0.88 = 0.681472

Step 2: Multiply by the starting value.

24000×0.681472=16355.32824000 \times 0.681472 = 16355.328

Step 3: Round to the nearest dollar.

16355.3281635516355.328 \approx 16355

Value after 3 years=16355 dollars\text{Value after 3 years} = \boxed{16355}\ \text{dollars}

Note: doing three separate steps gives the same result. Year 1: 24000×0.88=2112024000 \times 0.88 = 21120; year 2: 21120×0.88=18585.6021120 \times 0.88 = 18585.60; year 3: 18585.60×0.88=16355.32818585.60 \times 0.88 = 16355.328. ✓


Part (c): Compound interest

For compound interest at 4 per cent per year, each year’s value is multiplied by:

100%+4%=1.04100\% + 4\% = 1.04

Over 5 years the amount is:

A=3500×(1.04)5A = 3500 \times (1.04)^{5}

Step 1: Evaluate the multiplier.

(1.04)5=1.2166529024(1.04)^{5} = 1.2166529024

Step 2: Find the total amount.

A=3500×1.2166529024=4258.2851A = 3500 \times 1.2166529024 = 4258.2851\ldots

Rounded to 2 decimal places, the amount is $4258.29.

Step 3: Subtract the original investment to find the interest earned.

The question asks for the interest, not the total amount, so subtract the principal:

interest=4258.28513500=758.2851\text{interest} = 4258.2851\ldots - 3500 = 758.2851\ldots

Interest earned=758.29 dollars\text{Interest earned} = \boxed{758.29}\ \text{dollars}

Check: this is larger than the simple-interest amount 3500×0.04×5=7003500 \times 0.04 \times 5 = 700 (that is, $700), as expected for compound interest. ✓