Atomic Structure: Question 4

Syllabus 1.1, 1.2, 1.3, 1.4

Structured AS 5 marks

Phosphorus has proton number 15.

(a) Write the full electronic configuration of a phosphorus atom, using subshell notation. [1]

(b) The three electrons in phosphorus's outermost occupied sub-shell each occupy a separate orbital, with parallel spins, before any orbital contains a pair of electrons. State the name of the rule that describes this behaviour, and explain, in terms of electron-electron repulsion, why electrons arrange themselves this way. [2]

(c) Deduce the full electronic configuration of the phosphide ion, P3\text{P}^{3-}, and name the noble gas that has the same electronic configuration as this ion. [2]

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Worked solution

Part (a): Full electronic configuration of phosphorus

Phosphorus has proton number 15, so a neutral atom has 15 electrons. Filling the sub-shells in order of increasing energy (1s1s, 2s2s, 2p2p, 3s3s, 3p3p, …), each up to its maximum capacity where possible:

1s22s22p63s23p31s^2\,2s^2\,2p^6\,3s^2\,3p^3

Check the total: 2+2+6+2+3=152+2+6+2+3 = 15 ✓, matching the proton number.

Part (b): Hund’s rule in the 3p sub-shell

The outermost occupied sub-shell, 3p3p, contains three orbitals of equal energy (3px3p_x, 3py3p_y, 3pz3p_z) and three electrons to place in them. The rule that governs how they are arranged is Hund’s rule (the rule of maximum multiplicity): electrons occupy separate orbitals of equal energy singly, with parallel (unpaired) spins, before any orbital receives a second electron.

This happens because electrons are all negatively charged and repel one another. Placing each electron in its own 3p3p orbital keeps the three electrons, on average, further apart in space than would be the case if two of them were forced to share a single orbital while a third orbital stayed empty. Less electron-electron repulsion means lower overall energy, so the singly-occupied, parallel-spin arrangement is the more stable, ground-state configuration.

Part (c): The phosphide ion, P³⁻

The phosphide ion P3\text{P}^{3-} has gained three extra electrons compared with the neutral atom:

electrons in P3=15+3=18\text{electrons in P}^{3-} = 15 + 3 = 18

Continuing to fill sub-shells in order from the neutral atom’s configuration, the 3p3p sub-shell (currently 3p33p^3) fills up to its maximum of six before any new sub-shell would be needed:

1s22s22p63s23p61s^2\,2s^2\,2p^6\,3s^2\,3p^6

Check: 2+2+6+2+6=182+2+6+2+6 = 18 ✓.

This is exactly the electronic configuration of the noble gas argon (proton number 18). P3\text{P}^{3-} is described as isoelectronic with argon, since both species have the same number and arrangement of electrons, even though they have different numbers of protons.

Final answers

  • (a) 1s22s22p63s23p3\boxed{1s^2\,2s^2\,2p^6\,3s^2\,3p^3}
  • (b) Hund’s rule: the three 3p3p electrons occupy separate orbitals with parallel spins, minimising electron-electron repulsion.
  • (c) 1s22s22p63s23p6\boxed{1s^2\,2s^2\,2p^6\,3s^2\,3p^6}, the same configuration as argon.