Equilibria: Chemistry 9701 (Cambridge International AS & A Level)

Syllabus 7.1, 7.2, 25.1, 25.2 · Strand 1 Physical Chemistry

Questions
10
Total marks
55
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10 Core

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  • 25.1 3 questions
  • 25.2 2 questions
  • 7.1 5 questions
  • 7.2 2 questions

A reversible reaction in a closed system reaches dynamic equilibrium when forward and reverse rates are equal, so concentrations stop changing even though both reactions continue (syllabus ref 7.1 to 7.2). Le Chatelier’s principle predicts how a change in concentration, pressure or temperature shifts this position, while an equilibrium constant (KcK_c in terms of concentrations, or KpK_p in terms of partial pressures) quantifies it; only a temperature change alters the value of KK itself. The Brønsted–Lowry theory defines acids and bases as proton donors and acceptors, distinguishing a fully dissociated strong acid from a partially dissociated weak one.

The A Level sections (25.1 to 25.2) build on this. Using KaK_a, pKapK_a and Kw=[H+][OH]K_w = [\text{H}^+][\text{OH}^-], you can calculate the pH of strong acids/alkalis, weak acids, and buffer solutions, which resist pH change because they contain a reservoir of both a weak acid and its conjugate base. The solubility product, KspK_{sp}, extends equilibrium ideas to sparingly soluble salts, including the common-ion effect, while a partition coefficient, KpcK_{pc}, describes how a solute distributes between two immiscible solvents at equilibrium.

The exercises below are original, each followed by a complete worked solution.

Question 1

Multiple choice AS 1 mark

A gaseous equilibrium is established in a sealed, rigid container of fixed volume:

X(g)+Y(g)2Z(g)ΔH=114 kJ mol1\text{X(g)} + \text{Y(g)} \rightleftharpoons 2\text{Z(g)} \qquad \Delta H = -114\ \text{kJ mol}^{-1}

With no other change made to the system, the temperature of the container is then lowered.

Which row correctly describes the effect on the position of equilibrium and on the value of KcK_c?

Question 2

Structured AS 6 marks

Phosphorus pentachloride decomposes reversibly at high temperature:

PCl5(g)PCl3(g)+Cl2(g)\text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g)

A chemist places 0.400 mol0.400\ \text{mol} of PCl5(g)\text{PCl}_5(g) in an evacuated 2.00 dm32.00\ \text{dm}^3 container and allows the system to reach dynamic equilibrium at constant temperature. At equilibrium, 0.280 mol0.280\ \text{mol} of PCl5(g)\text{PCl}_5(g) remains.

(a) Write the expression for KcK_c for this equilibrium. [1]

(b) Calculate the equilibrium concentration, in mol dm3\text{mol dm}^{-3}, of PCl5\text{PCl}_5, PCl3\text{PCl}_3 and Cl2\text{Cl}_2. [3]

(c) Calculate KcK_c for this equilibrium, including its units, to 3 significant figures. [2]

Question 3

Structured AS 8 marks

Bromine and chlorine gases react reversibly to form bromine monochloride:

Br2(g)+Cl2(g)2BrCl(g)\text{Br}_2(g) + \text{Cl}_2(g) \rightleftharpoons 2\text{BrCl}(g)

Since Br2\text{Br}_2, Cl2\text{Cl}_2 and BrCl\text{BrCl} are all gases, this is a homogeneous equilibrium: every species present is in the same (gaseous) phase. A gaseous equilibrium mixture of Br2\text{Br}_2, Cl2\text{Cl}_2 and BrCl\text{BrCl} is established in a sealed container at constant temperature. At equilibrium, the total pressure is 200 kPa200\ \text{kPa}, and the mole fractions of Br2\text{Br}_2, Cl2\text{Cl}_2 and BrCl\text{BrCl} are 0.200.20, 0.200.20 and 0.600.60 respectively.

(a) Calculate the partial pressure, in kPa, of each of the three gases at equilibrium. [3]

(b) Write the expression for KpK_p, and use your answers to (a) to calculate its value. State whether KpK_p has units, explaining your reasoning. [3]

(c) State and explain the effect, if any, on the value of KpK_p of increasing the total pressure at constant temperature. [2]

Question 4

Structured A2 9 marks

Lactic acid (2-hydroxypropanoic acid), CH3CH(OH)COOH\text{CH}_3\text{CH(OH)COOH}, is a weak monobasic acid with Ka=1.4×104 mol dm3K_a = 1.4\times10^{-4}\ \text{mol dm}^{-3} at 298 K.

(a) Calculate the pH of a 0.200 mol dm30.200\ \text{mol dm}^{-3} solution of lactic acid, stating clearly any assumption you make. [4]

(b) A buffer solution is prepared containing 0.100 mol dm30.100\ \text{mol dm}^{-3} lactic acid and 0.150 mol dm30.150\ \text{mol dm}^{-3} sodium lactate, CH3CH(OH)COONa\text{CH}_3\text{CH(OH)COONa}. Calculate the pH of this buffer solution. [3]

(c) A few drops of dilute hydrochloric acid are added to the buffer solution in (b). Explain, in terms of the species present, why the pH of the buffer changes only very slightly. [2]

Question 5

Structured A2 7 marks

Lead(II) iodide, PbI2\text{PbI}_2, is a sparingly soluble ionic solid that establishes the following equilibrium in contact with water:

PbI2(s)Pb2+(aq)+2I(aq)\text{PbI}_2(s) \rightleftharpoons \text{Pb}^{2+}(aq) + 2\text{I}^-(aq)

(a) Write the expression for the solubility product, KspK_{sp}, of PbI2\text{PbI}_2. [1]

(b) The molar solubility of PbI2\text{PbI}_2 in pure water at 298 K is 1.5×103 mol dm31.5\times10^{-3}\ \text{mol dm}^{-3}. Calculate KspK_{sp} for PbI2\text{PbI}_2, including its units. [3]

(c) Calculate the molar solubility of PbI2\text{PbI}_2 in a 0.10 mol dm30.10\ \text{mol dm}^{-3} solution of potassium iodide, using your value of KspK_{sp} from (b). Comment briefly on how this compares with the solubility in pure water. [3]

Question 6

Multiple choice AS 1 mark

Solid ammonium chloride decomposes reversibly on heating to form two gases, in a sealed container at constant temperature:

NH4Cl(s)NH3(g)+HCl(g)\text{NH}_4\text{Cl(s)} \rightleftharpoons \text{NH}_3\text{(g)} + \text{HCl(g)}

This is a heterogeneous equilibrium, since the solid and the two gases are not all in the same phase.

Which expression is correct for KcK_c of this equilibrium?

Question 7

Structured AS 8 marks

Dinitrogen tetroxide dissociates reversibly in the gas phase:

N2O4(g)2NO2(g)\text{N}_2\text{O}_4\text{(g)} \rightleftharpoons 2\text{NO}_2\text{(g)}

0.0500 mol0.0500\ \text{mol} of N2O4(g)\text{N}_2\text{O}_4\text{(g)} is placed in an evacuated, sealed container and allowed to reach dynamic equilibrium at constant temperature. At equilibrium, 60.0%60.0\% of the N2O4\text{N}_2\text{O}_4 originally present has dissociated, and the total equilibrium pressure is 100 kPa100\ \text{kPa}.

(a) Write the expression for KpK_p for this equilibrium. [1]

(b) Calculate the amount, in mol, of N2O4(g)\text{N}_2\text{O}_4\text{(g)} and of NO2(g)\text{NO}_2\text{(g)} present at equilibrium, and hence the mole fraction of each gas. [3]

(c) Use your answers to (b) to calculate the partial pressure, in kPa, of each gas at equilibrium. [2]

(d) Calculate KpK_p for this equilibrium, stating its units. [2]

Question 8

Multiple choice A2 1 mark

Methanoic acid reacts reversibly with water:

HCOOH(aq)+H2O(l)HCOO(aq)+H3O+(aq)\text{HCOOH(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{HCOO}^-\text{(aq)} + \text{H}_3\text{O}^+\text{(aq)}

According to the Brønsted-Lowry theory, which pair of species is a conjugate acid-base pair?

Question 9

Structured A2 7 marks

At 298 K298\ \text{K}, the ionic product of water is Kw=[H+][OH]=1.00×1014 mol2 dm6K_w = [\text{H}^+][\text{OH}^-] = 1.00\times10^{-14}\ \text{mol}^2\ \text{dm}^{-6}.

(a) Hydrochloric acid, HCl\text{HCl}, is a strong monobasic acid that dissociates completely in water. Calculate the pH of a 0.0250 mol dm30.0250\ \text{mol dm}^{-3} solution of HCl\text{HCl} at 298 K298\ \text{K}. [2]

(b) Sodium hydroxide, NaOH\text{NaOH}, is a strong base that dissociates completely in water. Calculate the pH of a 0.0250 mol dm30.0250\ \text{mol dm}^{-3} solution of NaOH\text{NaOH} at 298 K298\ \text{K}, using KwK_w. [3]

(c) The dissociation of water, H2O(l)H+(aq)+OH(aq)\text{H}_2\text{O(l)} \rightleftharpoons \text{H}^+\text{(aq)} + \text{OH}^-\text{(aq)}, is endothermic. State and explain what happens to the value of KwK_w, and to the pH of pure water, as the temperature is raised above 298 K298\ \text{K}. Explain why pure water remains neutral at the higher temperature even though its pH is no longer 7.007.00. [2]

Question 10

Structured A2 7 marks

Iodine, I2\text{I}_2, distributes itself between water and hexane, two immiscible solvents, reaching a partition equilibrium at 298 K298\ \text{K}:

I2(aq)I2(hexane)\text{I}_2\text{(aq)} \rightleftharpoons \text{I}_2\text{(hexane)}

(a) Write the expression for the partition coefficient, KpcK_{pc}, of iodine between hexane and water. [1]

(b) In one experiment, the equilibrium concentration of iodine in the aqueous layer is 2.50×104 mol dm32.50\times10^{-4}\ \text{mol dm}^{-3}, and in the hexane layer is 2.05×102 mol dm32.05\times10^{-2}\ \text{mol dm}^{-3}. Calculate KpcK_{pc}. [2]

(c) In a second experiment at the same temperature, 25.0 cm325.0\ \text{cm}^3 of aqueous iodine solution of concentration 1.00×103 mol dm31.00\times10^{-3}\ \text{mol dm}^{-3} is shaken with 10.0 cm310.0\ \text{cm}^3 of hexane until partition equilibrium is re-established. Given that KpcK_{pc} is unchanged, use conservation of the total amount of iodine to calculate the new equilibrium concentration of iodine in the aqueous layer. [4]