Reaction Kinetics: Question 6

Syllabus 26.1

Multiple choice A2 1 mark

The concentration of a reactant, R, is followed over time for three separate reactions, each involving only R (all other reactants, if any, are in large excess so their concentration does not change).

  • Reaction 1: a graph of [R][\text{R}] against time is a straight line with a constant negative gradient. [R][\text{R}] falls by the same amount in every equal time interval.
  • Reaction 2: a graph of [R][\text{R}] against time is a curve for which the time taken for [R][\text{R}] to halve is the same at every stage, regardless of the concentration at the start of that stage.
  • Reaction 3: a graph of [R][\text{R}] against time is a curve for which the time taken for [R][\text{R}] to halve becomes progressively longer as the reaction proceeds.

Which row correctly gives the order of reaction with respect to R for Reactions 1, 2 and 3?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Reaction 1. Constant gradient

A straight-line graph of [R][\text{R}] against time, with a constant gradient, means that [R][\text{R}] decreases by the same amount every second. The rate of loss of R is constant and does not depend on how much R is left. This is the defining feature of a zero-order reaction with respect to R: rate=k[R]0=k\text{rate} = k[\text{R}]^0 = k.

Step 2: Reaction 2. Constant half-life

A curve for which the time taken for [R][\text{R}] to halve is always the same, no matter what the starting concentration for that stage is, has a constant half-life. A constant half-life, independent of concentration, is the defining feature of a first-order reaction with respect to R.

Step 3: Reaction 3. Increasing half-life

A curve for which the half-life becomes progressively longer as the reaction proceeds (i.e. as [R][\text{R}] falls) is characteristic of a second-order reaction. As [R][\text{R}] decreases, the rate ([R]2\propto [\text{R}]^2) falls away much more steeply than for a first-order reaction, so it takes longer and longer for the remaining R to halve.

Step 4: Matching to the options

Reaction 1 = zero order, Reaction 2 = first order, Reaction 3 = second order, this matches option A.

  • B swaps the zero- and first-order descriptions.
  • C and D both misassign the second-order (increasing half-life) behaviour to the wrong reaction.

Final answer

  • A\boxed{\text{A}}. Reaction 1 zero order, Reaction 2 first order, Reaction 3 second order.