Functions: Question 9

Syllabus 1.2

Multiple choice AS 1 mark

The functions ff and gg are defined, for xRx \in \mathbb{R}, by f(x)=x21andg(x)=3x.f(x) = x^2 - 1 \qquad \text{and} \qquad g(x) = 3 - x.

What is the value of gf(2)gf(-2)?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Understand the order of composition

gf(2)gf(-2) means g(f(2))g(f(-2)), apply ff first, then apply gg to that result.

Step 2: Find f(2)f(-2)

f(2)=(2)21=41=3f(-2) = (-2)^2 - 1 = 4 - 1 = 3

Step 3: Apply gg to this result

g(3)=33=0g(3) = 3 - 3 = 0

So gf(2)=0gf(-2) = 0.

Why the other options are wrong

  • B (33): this is just f(2)f(-2), the working stops one step too early, forgetting to apply gg.
  • C (2424): this comes from computing fg(2)fg(-2) instead, i.e. applying the functions in the wrong order: g(2)=5g(-2)=5, then f(5)=251=24f(5)=25-1=24.
  • D (88): this comes from a sign error, treating (2)2(-2)^2 as 4-4 so that f(2)f(-2) is wrongly found to be 5-5, then g(5)=3(5)=8g(-5)=3-(-5)=8.

Final answer

gf(2)=0(Option A)\boxed{gf(-2) = 0} \quad \text{(Option A)}