Momentum: Question 6

Syllabus 4.3

Multiple choice AS 1 mark

A delivery drone of mass 4 kg4\text{ kg} flies horizontally in a straight line at a constant velocity of 12 m s112\text{ m s}^{-1}, directly away from its depot.

What is the magnitude of the drone's momentum?

Choose an answer to check it, then compare with the worked solution below.

Show worked solution Hide worked solution

Worked solution

Step 1: Recall the definition of momentum

Linear momentum is defined as mass times velocity: p=mvp = mv

Momentum is a vector, so its full description includes a direction, but here we are only asked for the magnitude.

Step 2: Substitute the given values

The drone has mass m=4 kgm=4\text{ kg} and speed v=12 m s1v=12\text{ m s}^{-1}: p=mv=4×12=48 kg m s1p = mv = 4 \times 12 = 48\text{ kg m s}^{-1}

Why the other options are wrong

  • B (16 kg m s116\text{ kg m s}^{-1}): this comes from adding the mass and velocity, 4+12=164+12=16, instead of multiplying them.
  • C (3 kg m s13\text{ kg m s}^{-1}): this comes from dividing velocity by mass, 12÷4=312\div4=3, instead of multiplying.
  • D (96 kg m s196\text{ kg m s}^{-1}): this is double the correct value, e.g. from mistakenly multiplying by 2m2m or 2v2v.

Final answer

  • Magnitude of momentum =48 kg m s1= \boxed{48}\text{ kg m s}^{-1}, option A.