Permutations and Combinations: Question 6

Syllabus 5.2

Multiple choice AS 1 mark

A café offers a meal deal in which a customer chooses exactly one starter from 44 different starters, exactly one main course from 66 different main courses, and exactly one dessert from 33 different desserts.

How many different meal deals can a customer choose?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Identify the three independent choices

The customer makes three separate decisions: which starter, which main course, and which dessert. Each choice is made from a different set of options, and every combination of starter, main and dessert is a distinct meal deal. Choosing pizza-then-fish is a different meal deal from choosing pizza-then-chicken.

Step 2: Apply the multiplication principle

Because the three choices are made independently, the total number of meal deals is the product of the numbers of options at each stage:

  • Starter: 44 ways
  • Main course: 66 ways
  • Dessert: 33 ways

4×6×3=72.4\times6\times3 = 72.

Step 3: Check by building up in stages

First combine starter and main course: there are 4×6=244\times6=24 starter-and-main combinations. Each of these 2424 combinations can then be paired with any of the 33 desserts:

24×3=72.24\times3 = 72.

Both methods agree: 7272.

Why the other options are wrong

  • A (1313): this comes from adding 4+6+34+6+3 instead of multiplying, but each meal deal needs one choice from each category, not just one choice from any single category.
  • B (1818): this is 6×36\times3, the number of main-and-dessert combinations only, it ignores the starter choice.
  • C (2424): this is 4×64\times6, the number of starter-and-main combinations only, it ignores the dessert choice.

Final answer

  • Number of different meal deals =72= \boxed{72}, option D.