Kinematics: Question 9

Syllabus 2.1

Multiple choice AS 1 mark

A go-kart is travelling at a constant velocity of 4.0 m s14.0\text{ m s}^{-1} along a straight track when the driver presses the accelerator, giving the go-kart a uniform acceleration of 2.0 m s22.0\text{ m s}^{-2} for a time of 5.0 s5.0\text{ s}.

What is the displacement of the go-kart during this 5.0 s5.0\text{ s}?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Identify the known quantities

The go-kart has an initial velocity u=4.0 m s1u=4.0\text{ m s}^{-1}, a uniform acceleration a=2.0 m s2a=2.0\text{ m s}^{-2}, and this acts for a time t=5.0 st=5.0\text{ s}. The displacement is required, so the appropriate suvat equation is: s=ut+12at2s = ut + \tfrac{1}{2}at^2

Step 2: Substitute the values

s=(4.0)(5.0)+12(2.0)(5.0)2s = (4.0)(5.0) + \tfrac{1}{2}(2.0)(5.0)^2 s=20+12(2.0)(25)s = 20 + \tfrac{1}{2}(2.0)(25) s=20+25s = 20 + 25 s=45 ms = 45\text{ m}

Why the other options are wrong

  • B (70 m70\text{ m}): comes from omitting the factor of 12\tfrac{1}{2}, calculating 20+(2.0)(25)=20+50=7020 + (2.0)(25) = 20+50=70.
  • C (20 m20\text{ m}): comes from including only the utut term and ignoring the acceleration’s contribution entirely.
  • D (25 m25\text{ m}): comes from including only the 12at2\tfrac{1}{2}at^2 term, as though the go-kart had started from rest rather than at 4.0 m s14.0\text{ m s}^{-1}.

Final answer

  • Displacement during the 5.0 s5.0\text{ s} =45 m= \boxed{45}\text{ m}, option A.