Atomic Structure and Isotopes: Question 7

Syllabus 2.2

Structured Core 6 marks

A structural engineer is testing an aluminium bracket that has a thin phosphorus-based fireproof coating. Separately, an agricultural chemist is checking the potassium content of a soil fertiliser. Aluminium has proton number 13, phosphorus has proton number 15, and potassium has proton number 19.

(a) Write the electronic configuration of an aluminium atom and of a phosphorus atom. [2]

(b) State the number of outer-shell electrons in an aluminium atom and in a phosphorus atom, and hence give the group number of each element. [2]

(c) Write the electronic configuration of a potassium atom and state which group of the Periodic Table potassium is in. [2]

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Worked solution

Part (a): Electronic configuration of aluminium and phosphorus

Electrons fill shells from the innermost outward, with a maximum of 2 in the first shell and up to 8 in the second and third shells (for these proton numbers).

  • Aluminium (proton number 1313): 2,8,32, 8, 3
  • Phosphorus (proton number 1515): 2,8,52, 8, 5

Part (b): Outer-shell electrons and group number

  • Aluminium’s outer shell has 33 electrons, so aluminium is in Group III.
  • Phosphorus’s outer shell has 55 electrons, so phosphorus is in Group V.

For Groups I to VII, the number of outer-shell electrons is equal to the group number.

Part (c): Electronic configuration of potassium

Potassium has proton number 1919. The first shell holds 22 electrons and the second shell holds 88, using 1010 electrons. The third shell can hold up to 88 more, using a further 88 electrons (1818 so far). The 1919th electron cannot fit into the third shell (already full at 88), so it starts a new, fourth shell:

2,8,8,12, 8, 8, 1

Potassium has 11 outer-shell electron, so it is in Group I.

Final answers

  • (a) Aluminium: 2,8,32,8,3; phosphorus: 2,8,52,8,5.
  • (b) Aluminium is in Group III\boxed{\text{Group III}}; phosphorus is in Group V\boxed{\text{Group V}}.
  • (c) Potassium: 2,8,8,12,8,8,1, in Group I\boxed{\text{Group I}}.