Reactivity Series and Metal Extraction: Question 5

Syllabus 9.6

Multiple choice Core 1 mark

Four hypothetical metals, J, K, L and M, have positions in the reactivity series relative to carbon given by

J>K>carbon>L>MJ > K > \text{carbon} > L > M

(with J the most reactive and M the least reactive of the five).

Which statement about extracting these metals from their ores is correct?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Recall the rule linking reactivity to extraction method

The ease of obtaining a metal from its ore depends on its position in the reactivity series:

  • Metals above carbon are too reactive to be displaced by carbon, so they must be extracted using electrolysis.
  • Metals below carbon are less reactive than carbon, so carbon can reduce their ores by removing the oxygen. These metals can be extracted by heating with carbon.

Step 2: Apply the rule to J, K, L and M

The given order is J>K>carbon>L>MJ > K > \text{carbon} > L > M, so:

  • J and K are above carbon \rightarrow they need electrolysis.
  • L and M are below carbon \rightarrow they can be extracted by heating with carbon.

Step 3: Check each option

  • A: J is above carbon, so it needs electrolysis, not carbon reduction, incorrect.
  • B: K is above carbon, so it needs electrolysis, not carbon reduction, incorrect.
  • C: L is below carbon, so heating its oxide with carbon will reduce it to the metal, correct.
  • D: M is below carbon, so it can be extracted more cheaply by carbon reduction; electrolysis is not the only method, incorrect.

Final answer

  • L can be extracted by heating its oxide with carbon, option C.