Redox Reactions: Question 8

Syllabus 6.4

Multiple choice Extended 1 mark

Aqueous iron(II) sulfate, FeSO4\text{FeSO}_4, is oxidised by an excess of acidified aqueous potassium manganate(VII). In the resulting solution, the oxidation number of iron has changed to +3+3.

What is the correct name of the iron-containing product formed?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Recall how oxidation numbers are used in naming

When an element can have more than one oxidation number in its compounds, a Roman numeral is placed immediately after the element’s name to show its oxidation number in that particular compound, for example iron(II) or iron(III).

Step 2: Apply the given oxidation number

The question states that the oxidation number of iron in the product is +3+3. This is shown by the Roman numeral (III) placed directly after “iron”.

Step 3: Name the compound

The iron is combined with sulfate ions, so the correct name is iron(III) sulfate.

Step 4: Check against the options

  • Option A keeps the original oxidation number (+2+2), which is incorrect after oxidation.
  • Option C places the Roman numeral in the wrong position.
  • Option D wrongly uses the formula subscript (33 from Fe2(SO4)3\text{Fe}_2(\text{SO}_4)_3) as if it were the oxidation number.
  • Option B correctly names the product using the oxidation number of +3+3.

Final answer

  • The product is iron(III) sulfate, option B.