Electric Circuits and Resistance: Question 5

Syllabus 4.2.3

Multiple choice Core 1 mark

A charge of 5.0 C5.0\text{ C} passes through a resistor, transferring 40 J40\text{ J} of electrical energy to the resistor as it does so. What is the potential difference across the resistor?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Step 1: Recall the relationship between p.d. energy and charge

Potential difference is the energy transferred per unit charge:

V=WQV = \frac{W}{Q}

Step 2: Substitute the values

The energy transferred is W=40 JW = 40\text{ J} and the charge is Q=5.0 CQ = 5.0\text{ C}:

V=40 J5.0 CV = \frac{40\text{ J}}{5.0\text{ C}}

Step 3: Work out the potential difference

V=8.0 VV = 8.0\text{ V}

Why the other options are wrong

OptionHow it arisesError
0.125 V0.125\text{ V}5.0÷405.0 \div 40Formula inverted (charge ÷ energy)
45 V45\text{ V}40+5.040 + 5.0Added instead of dividing
200 V200\text{ V}40×5.040 \times 5.0Multiplied instead of dividing

Final answers

  • Potential difference =8.0 V= \boxed{8.0\text{ V}}, option B