Energy, Work and Power: Question 1

Syllabus 1.7.2

Multiple choice Core 1 mark

A warehouse worker pushes a loaded trolley across a level floor with a steady horizontal force of 45 N45\text{ N}. The trolley moves a distance of 12 m12\text{ m} in the direction of the force. How much work is done on the trolley?

Choose an answer to check it, then compare with the worked solution below.

Show worked solution Hide worked solution

Worked solution

Step 1: Recall the equation for work done

Work done by a force is the force multiplied by the distance moved in the direction of the force:

W=FdW = Fd

Step 2: Substitute the values

W=45 N×12 mW = 45\text{ N} \times 12\text{ m}

Step 3: Work out the answer

W=540 JW = 540\text{ J}

Why the other options are wrong

OptionHow it arisesError
33 J33\text{ J}451245 - 12Subtracted instead of multiplying
57 J57\text{ J}45+1245 + 12Added instead of multiplying
3.8 J3.8\text{ J}45÷1245 \div 12Divided instead of multiplying

Final answers

  • Work done =540 J= \boxed{540\text{ J}}, option B