Energy, Work and Power: Question 10

Syllabus 1.7.2, 1.7.4

Structured Extended 7 marks

A student of mass 60 kg60\text{ kg} climbs a flight of stairs of total vertical height 4.5 m4.5\text{ m} in a time of 12 s12\text{ s}. Take gravitational field strength g=10 N/kgg = 10\text{ N/kg}.

(a) Calculate the useful work done by the student in raising her own body up the stairs. [2]

(b) Calculate the useful power developed by the student while climbing the stairs. [2]

(c) The student's muscles are only 25%25\% efficient at converting chemical energy into this useful mechanical work; the rest is wasted. Calculate the total chemical energy transferred from the student's internal chemical energy store during the climb. [2]

(d) State the main form in which the wasted energy is transferred away from the student's body. [1]

Show worked solution Hide worked solution

Worked solution

Part (a): Useful work done

Climbing the stairs raises the student’s own weight through a vertical height, so the useful work done equals the gain in gravitational potential energy, W=mghW = mgh:

W=60×10×4.5W = 60 \times 10 \times 4.5

W=2700 JW = 2700\text{ J}

Part (b): Useful power developed

Power is the useful energy transferred per unit time:

P=Wt=2700 J12 sP = \frac{W}{t} = \frac{2700\text{ J}}{12\text{ s}}

P=225 WP = 225\text{ W}

Part (c): Chemical energy transferred

Efficiency compares the useful energy output with the total energy input:

efficiency=useful energy outputtotal energy input\text{efficiency} = \frac{\text{useful energy output}}{\text{total energy input}}

Rearranging for the total (chemical) energy input, with efficiency =25%=0.25= 25\% = 0.25:

total energy input=useful energy outputefficiency=27000.25\text{total energy input} = \frac{\text{useful energy output}}{\text{efficiency}} = \frac{2700}{0.25}

total energy input=10800 J\text{total energy input} = 10800\text{ J}

Part (d): Where the wasted energy goes

The 8100 J8100\text{ J} (10800 J2700 J10800\text{ J} - 2700\text{ J}) that is not usefully transferred to gravitational potential energy is mostly dissipated as heat, mainly through sweating and the warming of the skin and surrounding air as the muscles work.

Final answers

  • (a) Useful work done == 2700 J2700\text{ J}
  • (b) Useful power developed == 225 W225\text{ W}
  • (c) Chemical energy transferred == 10800 J10800\text{ J}
  • (d) Wasted energy is mostly transferred as heat