Forces and Newton’s Laws: Question 1
Syllabus 1.5.1
A skater is moving across smooth ice at a constant velocity in a straight line. At one instant, a friend pushes her forward with a horizontal force of , while air resistance acts on her with a horizontal force of in the opposite direction. What is the resultant force on the skater at this instant, and what happens to her velocity as a result?
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Worked solution
Step 1: Combine the forces along the same line
Both forces act on the skater along the same straight line but in opposite directions: forward (from the push) and backward (from air resistance). Forces acting in opposite directions along the same line are combined by subtraction:
Step 2: Apply Newton’s first law
Newton’s first law tells us that an object continues at rest, or continues moving in a straight line at a constant speed, unless it is acted on by a resultant (unbalanced) force. Here, the two forces are equal and opposite, so the resultant force is zero.
Step 3: Decide what happens to the skater’s velocity
The skater was already moving at a constant velocity before this instant. Since the resultant force acting on her is zero, nothing changes: she simply continues moving at exactly the same constant velocity. She does not speed up, slow down, or stop.
Why the other options are wrong
| Option | Reasoning given | Why it’s wrong |
|---|---|---|
| A ( forward, speeds up) | Added the forces instead of subtracting | The forces act in opposite directions, so they must be subtracted, not added |
| C (, stops immediately) | Correct resultant force, wrong conclusion | A zero resultant force means no change in motion. An object already moving keeps moving, it does not stop |
| D ( backward, decelerates) | Added the forces and assumed the resistive force “wins” | Again, the forces should be subtracted; also, equal forces cannot produce a net force in either direction |
Final answers
- Resultant force
- The skater continues at her same constant velocity, option B