Forces, Density and Pressure: Question 1

Syllabus 4.1

Multiple choice AS 1 mark

A gate is hinged at one edge. A gardener pushes on the gate with a force of 40 N40\text{ N}, applied at right angles to the gate, at a point 1.2 m1.2\text{ m} from the hinge.

What is the moment of this force about the hinge?

Choose an answer to check it, then compare with the worked solution below.

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Worked solution

Setting up the problem

Since the force is applied at right angles (perpendicular) to the gate, the perpendicular distance from the hinge to the line of action of the force is simply the distance measured along the gate, 1.2 m1.2\text{ m}.

Calculating the moment

The moment of a force about a point is defined as: moment=force×perpendicular distance from the pivot to the line of action of the force\text{moment} = \text{force} \times \text{perpendicular distance from the pivot to the line of action of the force}

Substituting the values: moment=40 N×1.2 m\text{moment} = 40\text{ N} \times 1.2\text{ m} moment=48 N m\text{moment} = 48\text{ N m}

Why the other options are wrong

  • A (24 N m24\text{ N m}): this is half the correct value, from mistakenly halving the moment (perhaps confusing it with a couple, which is not relevant here since only one force acts).
  • B (33 N m33\text{ N m}): this comes from dividing FF by dd (40÷1.2=33.340 \div 1.2 = 33.3) instead of multiplying.
  • C (41 N m41\text{ N m}): this comes from adding the force and the distance (40+1.2=41.240 + 1.2 = 41.2) instead of multiplying them. A moment is always force ×\times distance, never a sum.

Final answer

  • Moment of the force about the hinge =48 N m= \boxed{48}\text{ N m}, option D.