Motion and Motion Graphs: Physics 0625 (Cambridge O Level / IGCSE)

Syllabus 1.2 · Strand 1 Motion, forces and energy

Questions
10
Total marks
62
Tier mix
6 Core · 4 Extended

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Syllabus coverage

  • 1.2 10 questions

Motion is where almost every 0625 course begins (syllabus 1.2). Speed is the distance travelled per unit time, v=stv = \dfrac{s}{t}, while velocity adds a direction; acceleration measures how quickly velocity changes, a=ΔvΔta = \dfrac{\Delta v}{\Delta t}. You must be able to calculate average speed from total distance over total time, and know that an object near the Earth’s surface falls with an almost constant acceleration of about 9.8 m/s29.8\ \text{m/s}^2 when air resistance is ignored.

Most marks in this topic come from graphs. On a distance–time graph, the gradient gives speed: a flat line means the object is at rest, a straight slope means constant speed, and a curve means the speed is changing. On a speed–time graph, the gradient gives acceleration and the area under the line gives distance travelled, a calculation examiners set almost every session, often for a journey built from several straight sections. Extended candidates also describe falling objects reaching terminal velocity as drag grows to balance weight.

The questions below are original, matched to this objective, and each comes with a full step-by-step worked solution.

Question 1

Multiple choice Core 1 mark

A distance–time graph is plotted for a runner during a training session. From t=0t = 0 to t=8 st = 8\text{ s}, the graph is a straight line and the distance increases steadily from 0 m0\text{ m} to 96 m96\text{ m}. From t=8 st = 8\text{ s} to t=20 st = 20\text{ s}, the graph is a horizontal straight line at a distance of 96 m96\text{ m}. What is the runner's speed during the first 8 s8\text{ s}, and what does the second section of the graph show about her motion?

Question 2

Structured Core 7 marks

A student travels from home to school. She first walks 400 m400\text{ m} to a bus stop, taking 300 s300\text{ s}. She then waits at the bus stop for 100 s100\text{ s} before the bus arrives. Finally, she travels 4500 m4500\text{ m} on the bus to school, taking 300 s300\text{ s}.

(a) Calculate the total distance she travels and the total time taken for the whole journey (including the time spent waiting), and use these to calculate her average speed for the whole journey. [3]

(b) On a distance–time graph for this journey, state what feature of the graph would be seen during the 100 s100\text{ s} she spends waiting at the bus stop, and explain why the graph has this feature. [2]

(c) As the bus pulls away from the stop, the distance–time graph for this part of the journey is a curve that gets steeper and steeper for the first 10 s10\text{ s}, before becoming a straight line. State whether the bus is accelerating or decelerating during this first 10 s10\text{ s}, and explain how you can tell this from the shape of the graph. [2]

Question 3

Structured Core 8 marks

A speed–time graph is recorded for a car during a short test on a straight, flat road. The graph has three straight-line sections:

  • From t=0t = 0 to t=8 st = 8\text{ s}: the speed increases steadily from 0 m/s0\text{ m/s} to 20 m/s20\text{ m/s}.
  • From t=8 st = 8\text{ s} to t=20 st = 20\text{ s}: the speed stays constant at 20 m/s20\text{ m/s}.
  • From t=20 st = 20\text{ s} to t=24 st = 24\text{ s}: the speed decreases steadily from 20 m/s20\text{ m/s} to 0 m/s0\text{ m/s}.

(a) State what the straight, sloping line between t=0t = 0 and t=8 st = 8\text{ s} shows about the way the car's speed is changing during this section. [1]

(b) Calculate the distance travelled by the car during the first section, from t=0t = 0 to t=8 st = 8\text{ s}, by finding the area between the graph and the time axis. [2]

(c) Calculate the distance travelled by the car during the second section, from t=8 st = 8\text{ s} to t=20 st = 20\text{ s}. [2]

(d) Calculate the total distance travelled by the car for the whole 24 s24\text{ s} test, from t=0t = 0 to t=24 st = 24\text{ s}. [3]

Question 4

Structured Extended 9 marks

A delivery drone flies in a straight line. Its speed at different times is shown below.

Time, tt / s Speed, vv / m/s Description
00 to 55 0150 \rightarrow 15 speed increases at a constant rate (straight line on graph)
55 to 1515 1515 (constant) speed stays constant
1515 to 2020 15015 \rightarrow 0 speed decreases at a constant rate (straight line on graph)

After t=20 st = 20\text{ s}, the drone speeds up again. From t=20 st = 20\text{ s} to t=30 st = 30\text{ s}, the speed–time graph for the drone is a curve that becomes less steep as time goes on (rather than a straight line).

(a) Calculate the acceleration of the drone during the first phase, from t=0t = 0 to t=5 st = 5\text{ s}. [2]

(b) State the acceleration of the drone during the second phase, from t=5 st = 5\text{ s} to t=15 st = 15\text{ s}, and explain your answer. [2]

(c) Calculate the acceleration of the drone during the third phase, from t=15 st = 15\text{ s} to t=20 st = 20\text{ s}. State whether your answer represents an acceleration or a deceleration, and explain how the sign of your answer shows this. [3]

(d) State what the shape of the graph during the fourth phase (from t=20 st = 20\text{ s} to t=30 st = 30\text{ s}) shows about the drone's acceleration, and explain how you can tell this from the graph. [2]

Question 5

Multiple choice Core 1 mark

A distance–time graph shows two hikers, P and Q, who start walking from the same point at the same time. Hiker P's line is a straight line from (0 s,0 m)(0\text{ s}, 0\text{ m}) to (40 s,240 m)(40\text{ s}, 240\text{ m}). Hiker Q's line is a straight line from (0 s,0 m)(0\text{ s}, 0\text{ m}) to (40 s,160 m)(40\text{ s}, 160\text{ m}). Which hiker is walking faster, and what is the difference between their speeds?

Question 6

Structured Core 7 marks

A cyclist sets off from her house and rides in a straight line to a park, stops to rest, then rides back home along the same route. Her distance from home is recorded throughout the journey:

  • From t=0t = 0 to t=300 st = 300\text{ s}: her distance from home increases steadily from 0 m0\text{ m} to 1500 m1500\text{ m}.
  • From t=300 st = 300\text{ s} to t=420 st = 420\text{ s}: her distance from home stays constant at 1500 m1500\text{ m}.
  • From t=420 st = 420\text{ s} to t=570 st = 570\text{ s}: her distance from home decreases steadily from 1500 m1500\text{ m} back to 0 m0\text{ m}.

(a) Calculate the cyclist's speed during the first section of the journey, from t=0t = 0 to t=300 st = 300\text{ s}. [2]

(b) State what the cyclist is doing between t=300 st = 300\text{ s} and t=420 st = 420\text{ s}, and explain how you can tell this from the graph. [2]

(c) Calculate the cyclist's speed during the final section of the journey, from t=420 st = 420\text{ s} to t=570 st = 570\text{ s}. [2]

(d) Explain how the graph shows that, during this final section, the cyclist is travelling back towards home rather than continuing to travel further away from home. [1]

Question 7

Structured Core 10 marks

A hot air balloon pilot practises controlling the balloon's height during a short test flight over flat ground. The balloon's height above the ground is recorded throughout the flight:

  • From t=0t = 0 to t=40 st = 40\text{ s}: the height increases steadily (a straight line on the graph) from 0 m0\text{ m} to 300 m300\text{ m}.
  • From t=40 st = 40\text{ s} to t=100 st = 100\text{ s}: the height continues to increase steadily (a straight line, but with a shallower gradient) from 300 m300\text{ m} to 480 m480\text{ m}.
  • From t=100 st = 100\text{ s} to t=160 st = 160\text{ s}: the pilot begins a controlled descent. The height decreases from 480 m480\text{ m} to 120 m120\text{ m}, but this section of the graph is a curve, not a straight line: it is steep immediately after t=100 st = 100\text{ s} and becomes less steep as tt approaches 160 s160\text{ s}.

(a) Calculate the balloon's ascent speed during the first section, from t=0t = 0 to t=40 st = 40\text{ s}. [2]

(b) Calculate the balloon's ascent speed during the second section, from t=40 st = 40\text{ s} to t=100 st = 100\text{ s}. State which of the two ascent sections has the greater speed, and explain how this is shown by the steepness of the two lines. [2]

(c) State whether the balloon's descent speed during the third section is constant, increasing, or decreasing, and explain how you can tell this from the shape of the graph. [2]

(d) Calculate the balloon's average descent speed for the whole third section, from t=100 st = 100\text{ s} to t=160 st = 160\text{ s}. Explain why this value is not equal to the balloon's actual descent speed at every instant during this section. [3]

(e) Calculate the total distance travelled by the balloon (vertically) during the whole 160 s160\text{ s} flight described above. [1]

Question 8

Multiple choice Extended 1 mark

A speed–time graph is recorded for a skateboarder riding down a ramp and then braking. From t=0t = 0 to t=4 st = 4\text{ s}, her speed increases steadily from 2 m/s2\text{ m/s} to 10 m/s10\text{ m/s}. From t=4 st = 4\text{ s} to t=6 st = 6\text{ s}, she brakes, and her speed decreases steadily from 10 m/s10\text{ m/s} to 0 m/s0\text{ m/s}. What is the magnitude of her acceleration while braking, and how does it compare with the magnitude of her acceleration during the first 4 s4\text{ s}?

Question 9

Structured Extended 10 marks

A train travels between two stations in a straight line. Its distance from the first station is recorded every so often, and the distance-time graph between each pair of readings is a straight line:

Time, tt / s 00 2020 5050 7070 9090
Distance, ss / m 00 400400 400400 800800 10001000

(a) Calculate the train's speed during the first section of the journey, from t=0t = 0 to t=20 st = 20\text{ s}. [2]

(b) State which section of the journey shows the train at rest, and explain how you can tell this from the table. [2]

(c) Calculate the train's speed during the section from t=50 st = 50\text{ s} to t=70 st = 70\text{ s}, and its speed during the section from t=70 st = 70\text{ s} to t=90 st = 90\text{ s}. [3]

(d) The train is approaching the second station at the end of the journey. State whether the train is speeding up or slowing down between the section in (c) covering t=50 st = 50\text{ s} to t=70 st = 70\text{ s} and the section covering t=70 st = 70\text{ s} to t=90 st = 90\text{ s}, and explain your answer. [1]

(e) Calculate the train's average speed for the whole 90 s90\text{ s} journey shown in the table. [2]

Question 10

Structured Extended 8 marks

A skydiver jumps from a stationary hot air balloon and falls vertically before opening her parachute. Her speed at various times after jumping is shown in the table below:

Time, tt / s 00 11 22 44 66 1010 1414
Speed, vv / m/s 00 9.89.8 19.419.4 3535 4444 5050 5050

(a) Calculate the skydiver's acceleration during the first second of the fall, from t=0t = 0 to t=1 st = 1\text{ s}, and compare your answer with the acceleration of free fall, g9.8 m/s2g \approx 9.8\text{ m/s}^2. [2]

(b) Show that the skydiver's acceleration between t=4 st = 4\text{ s} and t=6 st = 6\text{ s} is smaller than her acceleration between t=0t = 0 and t=1 st = 1\text{ s}. [3]

(c) State the term used for the speed the skydiver reaches after t=10 st = 10\text{ s}, and explain, in terms of the forces acting on her, why her speed stops increasing at this point. [3]