Probability: Mathematics 9709 (Cambridge International AS & A Level)

Syllabus 5.3 · Strand 5 Probability & Statistics 1

Questions
10
Total marks
55
Tier mix
10 Core

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  • 5.3 10 questions

Basic probability (syllabus ref 5.3) starts from counting: when every outcome in a sample space is equally likely, P(event)=number of favourable outcomestotal number of outcomesP(\text{event})=\dfrac{\text{number of favourable outcomes}}{\text{total number of outcomes}}, and for larger sample spaces, such as selecting a hand of cards, permutations or combinations from 5.2 do the counting for you. From there, two rules combine events: an addition rule for ”AA or BB” and a multiplication rule for ”AA and BB” (the latter simplifying to P(A)×P(B)P(A)\times P(B) specifically when AA and BB are independent, i.e. when P(AB)=P(A)×P(B)P(A\cap B)=P(A)\times P(B). A condition you can test directly by comparing both sides).

Conditional probability asks how the chance of AA changes once you know BB has happened, given by P(AB)=P(AB)P(B)P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}. This is often easiest to visualise with a tree diagram, where branch probabilities multiply along a path and separate paths to the same outcome are added, or with a sample-space diagram for problems like the total score on two dice or drawing coloured balls from a bag without replacement.

Original exam-style problems covering counting, combined events, independence and conditional probability, each with a complete worked solution, follow below.

Question 1

Multiple choice AS 1 mark

In a school raffle, tickets are numbered from 11 to 5050, and one winning ticket is drawn at random so that every number is equally likely.

What is the probability that the winning number is a multiple of 55 or a multiple of 88?

Question 2

Structured AS 8 marks

A fitness studio has 120120 members. Each member's attendance is recorded for two classes, Yoga and Spin, and summarised in the two-way table below.

Attends Spin Does not attend Spin Total
Attends Yoga 18 42 60
Does not attend Yoga 24 36 60
Total 42 78 120

One member is selected at random from the 120120 members.

(a) Find P(Yoga)P(\text{Yoga}) and P(Yoga and Spin)P(\text{Yoga and Spin}). [2]

(b) State, with a reason, whether the events "attends Yoga" and "attends Spin" are mutually exclusive. [1]

(c) Determine, showing your working, whether the events "attends Yoga" and "attends Spin" are independent. [3]

(d) Find P(SpinYoga)P(\text{Spin} \mid \text{Yoga}). [2]

Question 3

Structured AS 8 marks

QuickParcel Couriers dispatches all of its parcels from one of two hubs. Hub A dispatches 60%60\% of all parcels, and Hub B dispatches the remaining 40%40\%.

The probability that a parcel dispatched from Hub A arrives late is 0.050.05, and the probability that a parcel dispatched from Hub B arrives late is 0.100.10.

A parcel is selected at random.

(a) Find the probability that the parcel is dispatched from Hub A and arrives late. [2]

(b) Find the probability that the parcel arrives late. [3]

(c) Given that the parcel arrives late, find the probability that it was dispatched from Hub B. [3]

Question 4

Structured AS 9 marks

A warehouse has two smoke detectors fitted in the same storage room, Detector 1 and Detector 2, which operate independently of one another.

If a fire occurs, the probability that Detector 1 raises an alarm is 0.90.9, and independently, the probability that Detector 2 raises an alarm is 0.80.8.

Given that a fire occurs, find the probability that:

(a) both detectors raise the alarm; [2]

(b) neither detector raises the alarm; [2]

(c) at least one detector raises the alarm; [2]

(d) exactly one of the two detectors raises the alarm. [3]

Question 5

Multiple choice AS 1 mark

For two events AA and BB, it is given that P(A)=0.4P(A) = 0.4, P(B)=0.5P(B) = 0.5 and P(AB)=0.2P(A \cap B) = 0.2.

Which one of the following statements is correct?

Question 6

Multiple choice AS 1 mark

In a class of 4040 students, every student plays badminton, chess, both, or neither. The numbers in each category are shown in the table below.

Category Number of students
Badminton only 14
Chess only 6
Both badminton and chess 8
Neither 12

A student is selected at random from the class.

Given that the student plays badminton, what is the probability that they also play chess?

Question 7

Structured AS 9 marks

A box contains 1212 chocolates: 77 dark chocolates and 55 milk chocolates, otherwise identical in appearance. Three chocolates are selected at random from the box, all at the same time, so the order of selection does not matter.

(a) Find the total number of ways to choose 33 chocolates from the 1212, and hence find the probability that all three chocolates selected are dark. [3]

(b) Find the probability that exactly two of the three chocolates selected are dark (and one is milk). [3]

(c) Find the probability that at least one milk chocolate is selected. [3]

Question 8

Structured AS 8 marks

A bag contains 55 red balls and 33 blue balls, otherwise identical. Two balls are drawn at random from the bag, one after the other, without replacement.

(a) By considering the two stages of the draw, find P(both balls are red)P(\text{both balls are red}). [2]

(b) Find P(exactly one of the two balls is red)P(\text{exactly one of the two balls is red}). [3]

(c) Given that exactly one of the two balls drawn was red, find the probability that the red ball was drawn first. [3]

Question 9

Multiple choice AS 1 mark

Two fair six-sided dice, each numbered 11 to 66, are rolled together. Let AA be the event "the sum of the two scores is 99" and let BB be the event "the two dice show the same number (a double)".

What is P(A or B)P(A \text{ or } B)?

Question 10

Structured AS 9 marks

A magazine publisher surveys 200200 subscribers about whether they read Magazine XX, Magazine YY, both, or neither. The results are shown in the table below.

Category Number of subscribers
Reads XX only 54
Reads YY only 66
Reads both XX and YY 30
Reads neither 50

A subscriber is selected at random.

(a) Find P(X)P(X), P(Y)P(Y) and P(XY)P(X \cap Y). [2]

(b) Use the addition rule to find P(XY)P(X \cup Y), and hence find the probability that the subscriber reads neither magazine. [3]

(c) Determine, showing your working, whether the events "reads XX" and "reads YY" are independent. [2]

(d) Given that the subscriber does not read Magazine YY, find the probability that they read Magazine XX. [2]