Home › Subjects › Mathematics 9709 › Trigonometry Pure Mathematics 1 trigonometry (syllabus ref 1.5) extends sine, cosine and tangent beyond acute angles to any real input, measured in degrees or radians, and asks you to sketch graphs such as y = 3 sin x y=3\sin x y = 3 sin x or y = 1 − cos 2 x y=1-\cos 2x y = 1 − cos 2 x by tracking amplitude, period and vertical shift. Alongside the graphs come exact values (sin 30 ° = 1 2 \sin 30°=\tfrac12 sin 30° = 2 1 , cos 45 ° = 1 2 \cos 45°=\tfrac{1}{\sqrt2} cos 45° = 2 1 , tan 60 ° = 3 \tan 60°=\sqrt3 tan 60° = 3 , and their reflections into other quadrants) which examiners expect without a calculator.
Two identities do almost all the algebraic work in this topic: tan θ ≡ sin θ cos θ \tan\theta\equiv\dfrac{\sin\theta}{\cos\theta} tan θ ≡ cos θ sin θ and sin 2 θ + cos 2 θ ≡ 1 \sin^2\theta+\cos^2\theta\equiv 1 sin 2 θ + cos 2 θ ≡ 1 . They’re used to simplify expressions, prove further identities, and, most commonly, to rewrite an equation with mixed trig functions into a single one before solving. For instance, 3 sin 2 θ + 5 cos θ − 1 = 0 3\sin^2\theta+5\cos\theta-1=0 3 sin 2 θ + 5 cos θ − 1 = 0 becomes a quadratic in cos θ \cos\theta cos θ once sin 2 θ \sin^2\theta sin 2 θ is replaced by 1 − cos 2 θ 1-\cos^2\theta 1 − cos 2 θ . Solving trigonometric equations always comes with a stated interval (e.g. 0 ° ≤ θ ≤ 360 ° 0°\le\theta\le360° 0° ≤ θ ≤ 360° ), and the general solution isn’t required. Instead you find every root inside that interval by exploiting the periodicity and symmetry of each graph.
The worked examples below are original and set out full solution steps for each type of problem.
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01 Question Question 1 Multiple choice AS 1 mark The graph of y = 3 − 2 sin x y = 3 - 2\sin x y = 3 − 2 sin x is drawn for 0 ∘ ≤ x ≤ 360 ∘ 0^\circ \le x \le 360^\circ 0 ∘ ≤ x ≤ 36 0 ∘ .
What is the minimum value of y y y ?
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02 Question Question 2 Multiple choice AS 1 mark For an angle θ \theta θ where tan θ \tan\theta tan θ is defined and non-zero, which expression is equivalent to
sin θ tan θ \dfrac{\sin\theta}{\tan\theta} tan θ sin θ
for all such θ \theta θ ?
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03 Question Question 3 Structured AS 6 marks (a) Show that the equation
2 sin 2 x = 1 + cos x 2\sin^2 x = 1 + \cos x 2 sin 2 x = 1 + cos x
can be written in the form
2 cos 2 x + cos x − 1 = 0 2\cos^2 x + \cos x - 1 = 0 2 cos 2 x + cos x − 1 = 0 [2]
(b) Hence solve 2 sin 2 x = 1 + cos x 2\sin^2 x = 1 + \cos x 2 sin 2 x = 1 + cos x for 0 ∘ ≤ x ≤ 360 ∘ 0^\circ \le x \le 360^\circ 0 ∘ ≤ x ≤ 36 0 ∘ , giving all solutions. [4]
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04 Question Question 4 Structured AS 7 marks (a) Solve 2 cos 2 x − 1 = 0 2\cos 2x - 1 = 0 2 cos 2 x − 1 = 0 for 0 ∘ ≤ x ≤ 360 ∘ 0^\circ \le x \le 360^\circ 0 ∘ ≤ x ≤ 36 0 ∘ , giving all solutions. [5]
(b) Explain why part (a) has 4 solutions, rather than the 2 solutions that solving cos θ = 1 2 \cos\theta = \tfrac12 cos θ = 2 1 alone would suggest. [2]
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05 Question Question 5 Structured AS 6 marks (a) Show that the equation
2 sin x tan x = 3 2\sin x\tan x = 3 2 sin x tan x = 3
can be written in the form
2 cos 2 x + 3 cos x − 2 = 0 2\cos^2 x + 3\cos x - 2 = 0 2 cos 2 x + 3 cos x − 2 = 0 [3]
(b) Hence solve 2 sin x tan x = 3 2\sin x\tan x = 3 2 sin x tan x = 3 for 0 ≤ x ≤ 2 π 0 \le x \le 2\pi 0 ≤ x ≤ 2 π , giving your answers in terms of π \pi π . [3]
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06 Question Question 6 Multiple choice AS 1 mark What is the exact value of sin 210 ° \sin 210° sin 210° ?
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07 Question Question 7 Structured AS 6 marks The function y = 5 − 4 cos ( 2 x ) y = 5 - 4\cos(2x) y = 5 − 4 cos ( 2 x ) is defined for 0 ° ≤ x ≤ 360 ° 0° \le x \le 360° 0° ≤ x ≤ 360° .
(a) State the maximum value of y y y and the minimum value of y y y . [2]
(b) Find all values of x x x in the given interval at which the maximum value of y y y occurs. [2]
(c) Find all values of x x x in the given interval at which the minimum value of y y y occurs. [2]
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08 Question Question 8 Structured AS 6 marks (a) Prove that
sin θ tan θ + cos θ ≡ 1 cos θ \sin\theta\tan\theta + \cos\theta \equiv \dfrac{1}{\cos\theta} sin θ tan θ + cos θ ≡ cos θ 1
for all θ \theta θ where tan θ \tan\theta tan θ is defined. [4]
(b) Hence, or otherwise, find the exact value of sin 60 ° tan 60 ° + cos 60 ° \sin 60°\tan 60° + \cos 60° sin 60° tan 60° + cos 60° . [2]
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09 Question Question 9 Structured AS 7 marks (a) Show that the equation
2 cos 2 x − 5 sin x = 4 2\cos^2 x - 5\sin x = 4 2 cos 2 x − 5 sin x = 4
can be written in the form
2 sin 2 x + 5 sin x + 2 = 0 2\sin^2 x + 5\sin x + 2 = 0 2 sin 2 x + 5 sin x + 2 = 0 [3]
(b) Hence solve 2 cos 2 x − 5 sin x = 4 2\cos^2 x - 5\sin x = 4 2 cos 2 x − 5 sin x = 4 for 0 ≤ x ≤ 2 π 0 \le x \le 2\pi 0 ≤ x ≤ 2 π , giving your answers in terms of π \pi π . [4]
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10 Question Question 10 Multiple choice AS 1 mark The graph of y = sin ( 4 x ) y = \sin(4x) y = sin ( 4 x ) is drawn for x x x measured in degrees. What is the period of this graph?
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