D.C. Circuits: Physics 9702 (Cambridge International AS & A Level)

Syllabus 10.1, 10.2, 10.3 · Strand 3 Electricity and Circuits

Questions
10
Total marks
58
Tier mix
10 Core

0 of 10 questions completed

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Syllabus coverage

  • 10.1 6 questions
  • 10.2 8 questions
  • 10.3 2 questions

D.C. circuits (syllabus ref 10.1 to 10.3) puts the quantities from Electricity to work in real circuits. A source’s electromotive force (e.m.f.) is the energy transferred per unit charge driving charge around the whole circuit, which is larger than the terminal potential difference once the source’s internal resistance is accounted for. Kirchhoff’s first law (the sum of currents into a junction equals the sum out) follows from conservation of charge, and Kirchhoff’s second law (the sum of e.m.f.s around a loop equals the sum of potential drops) follows from conservation of energy; together they justify the combined-resistance formulae for resistors in series, R=R1+R2+R = R_1 + R_2 + \dots, and in parallel, 1R=1R1+1R2+\dfrac{1}{R} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dots, and let more complex networks be solved systematically.

A potential divider splits a supply voltage across two or more components in proportion to their resistance, providing a convenient reference or variable voltage; replacing one resistor with a thermistor or LDR turns the circuit into a sensor whose output potential difference varies with temperature or light intensity, a design used throughout the practical endorsement.

Original worked examples below solve full series/parallel networks and potential-divider circuits step by step.

Question 1

Multiple choice AS 1 mark

A junction inside a circuit has four wires connected to it. A current of 5.0 A5.0\text{ A} flows into the junction along one wire, and a current of 3.0 A3.0\text{ A} flows into the junction along a second wire. A current of 6.0 A6.0\text{ A} flows out of the junction along a third wire, and a current II flows out of the junction along the fourth wire.

What is the value of II?

Question 2

Structured AS 8 marks

A battery of e.m.f. 12 V12\text{ V} and negligible internal resistance is connected to a network of three resistors. A resistor of resistance 4.0 Ω4.0\ \Omega is connected in series with a parallel combination of two resistors, of resistance 6.0 Ω6.0\ \Omega and 12 Ω12\ \Omega.

(a) Calculate the combined resistance of the 6.0 Ω6.0\ \Omega and 12 Ω12\ \Omega resistors connected in parallel. [2]

(b) Calculate the total resistance of the complete network. [1]

(c) Calculate the total current supplied by the battery. [2]

(d) Calculate the current in the 6.0 Ω6.0\ \Omega resistor and the current in the 12 Ω12\ \Omega resistor, and show that these two currents are consistent with Kirchhoff's first law. [3]

Question 3

Structured AS 10 marks

A battery has e.m.f. 9.0 V9.0\text{ V} and internal resistance 0.50 Ω0.50\ \Omega. It is connected to a single external resistor of resistance 4.0 Ω4.0\ \Omega.

(a) Write down Kirchhoff's second law for this circuit, and use it to calculate the current II in the circuit. [3]

(b) Calculate the terminal potential difference of the battery. [2]

(c) Calculate the potential difference across the internal resistance (the "lost volts"). [2]

(d) Calculate the power dissipated in the internal resistance, and hence determine the efficiency of the transfer of energy from the battery to the external resistor. [3]

Question 4

Structured AS 8 marks

A potential divider circuit consists of a fixed resistor of resistance 2.0 kΩ2.0\text{ k}\Omega connected in series with a negative temperature coefficient (NTC) thermistor. This series combination is connected across a battery of e.m.f. 6.0 V6.0\text{ V} and negligible internal resistance. The output potential difference VoutV_{\text{out}} is taken across the thermistor.

At room temperature, the resistance of the thermistor is 8.0 kΩ8.0\text{ k}\Omega.

(a) State how the resistance of an NTC thermistor changes as its temperature increases. [1]

(b) Calculate VoutV_{\text{out}} at room temperature. [2]

(c) The temperature of the thermistor increases until its resistance falls to 2.0 kΩ2.0\text{ k}\Omega. Calculate the new value of VoutV_{\text{out}}. [2]

(d) State and explain how VoutV_{\text{out}} changes as the temperature of the thermistor increases, and suggest one practical device in which this potential divider circuit could be used. [3]

Question 5

Multiple choice AS 1 mark

A single-loop circuit contains two cells and a single resistor of resistance 4.0 Ω4.0\ \Omega. The two cells, each of negligible internal resistance, are connected so that their e.m.f.s oppose each other: one cell has e.m.f. 6.0 V6.0\text{ V} and the other has e.m.f. 2.0 V2.0\text{ V}, connected with reversed polarity relative to the first.

Using Kirchhoff's second law, what is the current in the circuit?

Question 6

Multiple choice AS 1 mark

Three resistors, each of resistance 4.0 Ω4.0\ \Omega, are connected in parallel with each other across a battery.

What is the combined resistance of the three resistors?

Question 7

Structured AS 10 marks

A student investigates a battery of e.m.f. EE and internal resistance rr by connecting it to a single external resistor of resistance RR and measuring the current II in the circuit.

With R=4.0 ΩR = 4.0\ \Omega, the current is I1=2.0 AI_1 = 2.0\text{ A}.

The 4.0 Ω4.0\ \Omega resistor is then replaced with a resistor of resistance R=9.0 ΩR = 9.0\ \Omega, and the current becomes I2=1.0 AI_2 = 1.0\text{ A}.

(a) Write down the Kirchhoff's second law equation for the circuit in each of the two cases, in terms of EE, rr and the given values of RR and II. [2]

(b) Solve your two equations simultaneously to find the values of EE and rr. [4]

(c) Using your values from (b), calculate the terminal potential difference of the battery in the first case (R=4.0 ΩR = 4.0\ \Omega). [2]

(d) Calculate the power dissipated inside the battery (i.e. in its internal resistance) in the second case (R=9.0 ΩR = 9.0\ \Omega). [2]

Question 8

Structured AS 8 marks

A potential divider circuit consists of a light-dependent resistor (LDR) connected in series with a fixed resistor of resistance 1.0 kΩ1.0\text{ k}\Omega. This series combination is connected across a battery of e.m.f. 9.0 V9.0\text{ V} and negligible internal resistance. The output potential difference VoutV_{\text{out}} is taken across the fixed resistor.

In darkness, the resistance of the LDR is 8.0 kΩ8.0\text{ k}\Omega.

(a) State how the resistance of an LDR changes as the light intensity falling on it increases. [1]

(b) Calculate VoutV_{\text{out}} in darkness. [2]

(c) The LDR is illuminated with bright light, causing its resistance to fall to 1.0 kΩ1.0\text{ k}\Omega. Calculate the new value of VoutV_{\text{out}}. [2]

(d) State and explain how VoutV_{\text{out}} changes as the light intensity increases, and suggest one practical device in which this potential divider circuit could be used. [3]

Question 9

Structured AS 10 marks

Two batteries, each of negligible internal resistance, are connected to a common resistor at a junction PP, forming a two-loop network.

  • A battery of e.m.f. 18 V18\text{ V} is connected to PP through a resistor of resistance 2.0 Ω2.0\ \Omega, carrying current I1I_1 towards PP.
  • A battery of e.m.f. 16 V16\text{ V} is connected to PP through a resistor of resistance 4.0 Ω4.0\ \Omega, carrying current I2I_2 towards PP.
  • From PP, a single resistor of resistance 3.0 Ω3.0\ \Omega carries current I3I_3 away from PP and back to the negative terminals of both batteries, which are joined together.

(a) State Kirchhoff's first law, and use it to write an equation relating I1I_1, I2I_2 and I3I_3 at junction PP. [2]

(b) Use Kirchhoff's second law to write one equation for the loop containing the 18 V18\text{ V} battery and the 3.0 Ω3.0\ \Omega resistor, and a second equation for the loop containing the 16 V16\text{ V} battery and the 3.0 Ω3.0\ \Omega resistor. [2]

(c) Solve your three equations from (a) and (b) simultaneously to find I1I_1, I2I_2 and I3I_3. [5]

(d) Calculate the potential difference across the 3.0 Ω3.0\ \Omega resistor. [1]

Question 10

Multiple choice AS 1 mark

A battery of e.m.f. 15 V15\text{ V} and negligible internal resistance is connected to a network of three resistors. A resistor of resistance 3.0 Ω3.0\ \Omega is connected in series with a parallel combination of two resistors, of resistance 6.0 Ω6.0\ \Omega and 3.0 Ω3.0\ \Omega.

What is the current in the 3.0 Ω3.0\ \Omega resistor of the parallel combination?